2y^2-3y-20/2y^2+y-10

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Solution for 2y^2-3y-20/2y^2+y-10 equation:


y in (-oo:+oo)

2*y^2-((20/2)*y^2)-(3*y)+y-10 = 0

2*y^2-10*y^2-3*y+y-10 = 0

-8*y^2-2*y-10 = 0

DELTA = (-2)^2-(-10*(-8)*4)

DELTA = -316

DELTA < 0

y belongs to the empty set

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